PSC MODEL QUESTION - 11
- The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
A.) 30
B.) 40
C.) 38
D.) 48
Answer: Option 'B'
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Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x
So, 6x = 48 or x = 8
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40 ✅
- The sides of a rectangle are in the ratio of 6 : 5 and its area is 1331 sq.m. Find the perimeter of rectangle.
A.) 120 m
B.) 121 cm
C.) 121 m
D.) None of these
Answer: Option 'C'
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Let 6x and 5x be sides of the rectangle
6x × 5x = 1331
11x^2 = 1331
x^2 = 1331/11 = 121 = x = 11
Length = 6x = 6 × 11 = 66
Breadth = 5x =5 × 11 = 55
Perimeter = 2 (l+b)
= 2 (66+55) = 121 m
= 2 (66+55) = 121 m
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- The sides of a rectangle are in the ratio of 6 : 5 and its area is 1331 sq.m. Find the perimeter of rectangle.
A.) 120 m
B.) 121 cm
C.) 121 m
D.) None of these
Answer: Option 'C'
✅

Let 6x and 5x be sides of the rectangle
6x × 5x = 1331
11x^2 = 1331
x^2 = 1331/11 = 121 = x = 11
Length = 6x = 6 × 11 = 66
Breadth = 5x =5 × 11 = 55
Perimeter = 2 (l+b)
= 2 (66+55) = 121 m
✅
= 2 (66+55) = 121 m
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